The solution for, sum of two numbers is 40. if one of them is 10 more than the other, find the numbers? Let, one number=x Second number=y One of the number is 10 more than other, y=10+x x+y=40 x+10+x=40 2x=40-10=30 2x=30 x=30/2=15 x=15, y=10+x=10+15=25 x=15,y=25
sum of two numbers is 40. if one of them is 10 more than the other, find the numbers.
Giri
The solution for, sum of two numbers is 40. if one of them is 10 more than the other, find the numbers? Let, one number=x Second number=y One of the number is 10 more than other, y=10+x x+y=40 x+10+x=40 2x=40-10=30 2x=30 x=30/2=15 x=15, y=10+x=10+15=25 x=15,y=25