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Aniya
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Aniya
Asked: February 16, 20212021-02-16T19:48:21+05:30 2021-02-16T19:48:21+05:30In: Maths Puzzles

A and B can do a work in 40 and 45 days respectively, begin work

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A and B can do a piece of work in 45 and 40 days respectively. they began the work together, but A leaves after same days and B finished the remaining work in 23 days. after how many did A leave.

a and b can do work in 40 and 45 days how to solve maths questionhow to solve a and b can work in 40 and 45 days respectivelymaths question
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    1 Answer

    1. Preeti Diwaker
      2021-03-19T10:48:58+05:30Added an answer on March 19, 2021 at 10:48 am

      As per question given in paragraph:

      A alone complete the work in = 45 days.

      B alone complete the work= 40 days

      Work of A =1/45

      Work of B=1/40

      Because time and work are inverse proportionate.

      Total work= 1/45+1/40= 360 units( take LCM of both the work)

      A make 360*1/45= 8 unit/day

      B make360*1/40= 9 units/day

      According to question A leaves the job after some day and remaining work is done by B alone in 23 days.

      So work of B after A leaves= 23 days*9 units/day= 207 units

      Work done by(A+B)= 360-207= 153 units

      A+B can make together (8+9)= 17 units per day.

      So the time after A leaves or he had worked together with B=153/17units =9days

       

      Hence A leaves his job after 9 days.

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